宇宙直播APP邀请码多少
发布网友
发布时间：2022-04-21 18:53
共2个回答
热心网友
时间：2023-06-15 17:20
灞曞紑鍏ㄩ儴
瀹囧畽www.FDH18.cn
鈭玿鈭氾紙x-1锛塪x
= 2/3 鈭?nbsp;x d锛坸-1锛塣(3/2)
= 2/3 [ x 锛坸-1锛塣(3/2) - 鈭?nbsp;( x-1锛塣(3/2) dx ]
= 2/3 [ x 锛坸-1锛塣(3/2) - 2/5 ( x-1锛塣(5/2) ] + C
热心网友
时间：2023-06-19 16:06
灞曞紑鍏ㄩ儴
瀹囧畽www.FDH18.cn
鈭玿鈭氾紙x-1锛塪x
= 2/3 鈭?nbsp;x d锛坸-1锛塣(3/2)
= 2/3 [ x 锛坸-1锛塣(3/2) - 鈭?nbsp;( x-1锛塣(3/2) dx ]
= 2/3 [ x 锛坸-1锛塣(3/2) - 2/5 ( x-1锛塣(5/2) ] + C
热心网友
时间：2023-07-01 23:09
宇宙www.FDH18.cn
∫x√（x-1）dx
= 2/3 ∫ x d（x-1）^(3/2)
= 2/3 [ x （x-1）^(3/2) - ∫ ( x-1）^(3/2) dx ]
= 2/3 [ x （x-1）^(3/2) - 2/5 ( x-1）^(5/2) ] + C
热心网友
时间：2023-07-01 23:10
宇宙直播邀请码 2HSIOY 都是大写的哦
